How to add a key value pair to a dictionary in Python
Learn how to add key-value pairs to a Python dictionary. This guide covers different methods, tips, real-world uses, and common error fixes.

Python dictionaries store data as key-value pairs, a core data structure for many applications. You can add new entries with simple bracket notation or use built-in methods.
In this article, we'll cover several techniques to add data, including the update() method. We'll also share practical tips, real-world examples, and advice to debug common dictionary errors.
Using square bracket notation to add a key-value pair
user_info = {"name": "John", "age": 30}
user_info["email"] = "[email protected]"
print(user_info)--OUTPUT--{'name': 'John', 'age': 30, 'email': '[email protected]'}
Using square brackets is the most direct way to add a single entry to a dictionary. In the example, the line user_info["email"] = "[email protected]" assigns a value to a new key. Python automatically creates the key "email" and assigns the corresponding value because the key isn't already in the dictionary.
This approach is efficient and idiomatic for adding one item at a time. It's also versatile. If the key had already existed, this same syntax would have updated its value. This dual functionality for both adding and updating makes it a fundamental tool for dictionary manipulation.
Basic dictionary modification methods
While square brackets handle single additions well, you can turn to methods like update(), dict.fromkeys(), and dictionary comprehensions for more complex operations.
Using the update() method to add key-value pairs
student = {"id": 101, "name": "Alice"}
student.update({"grade": "A", "course": "Python"})
print(student)--OUTPUT--{'id': 101, 'name': 'Alice', 'grade': 'A', 'course': 'Python'}
The update() method is your go-to for adding multiple key-value pairs at once. It takes another dictionary as its argument and merges its contents into the original, which is more efficient than adding items individually.
- Bulk additions: You can add any number of key-value pairs in a single call.
- Updates existing keys: If a key from the new dictionary already exists in the original, its value is updated.
In the example, update() seamlessly adds both the "grade" and "course" to the student dictionary.
Creating dictionaries with initial values using dict.fromkeys()
keys = ["apple", "banana", "cherry"]
fruit_dict = dict.fromkeys(keys, 0)
fruit_dict["mango"] = 5
print(fruit_dict)--OUTPUT--{'apple': 0, 'banana': 0, 'cherry': 0, 'mango': 5}
The dict.fromkeys() method is perfect for initializing a dictionary where multiple keys share the same starting value. It takes an iterable of keys and a single default value to assign to all of them. In the example, dict.fromkeys(keys, 0) quickly creates a dictionary where each fruit from the keys list is assigned the value 0.
- It’s an efficient way to set up a dictionary with default values before you populate it with specific data.
After creation, you can still add new key-value pairs, like fruit_dict["mango"] = 5, using standard methods.
Using dictionary comprehension to create and add items
original = {"a": 1, "b": 2}
new_items = {"c": 3, "d": 4}
combined = {**original, **new_items}
# Alternative using comprehension
combined_alt = {k: v for d in (original, new_items) for k, v in d.items()}
print(combined)--OUTPUT--{'a': 1, 'b': 2, 'c': 3, 'd': 4}
The double-asterisk operator ** provides a clean and modern way to merge dictionaries. By writing {**original, **new_items}, you're unpacking the contents of both dictionaries into a new one. It's a highly readable approach for combining multiple dictionaries in a single line.
- The dictionary comprehension shown is an alternative that builds the new dictionary by looping through each source dictionary's items.
- For simple merging, the
**operator is generally preferred for its clarity and conciseness.
Advanced dictionary techniques
For more complex tasks, you can move beyond basic assignments and use tools like setdefault() and defaultdict to handle keys that might not exist yet.
Using setdefault() to add keys conditionally
config = {"theme": "dark", "font_size": 12}
config.setdefault("language", "en") # Adds only if key doesn't exist
config.setdefault("theme", "light") # Does nothing as key exists
print(config)--OUTPUT--{'theme': 'dark', 'font_size': 12, 'language': 'en'}
The setdefault() method provides a safe way to add a key with a default value. It checks if a key exists; if not, it adds the key with the specified value. This prevents you from accidentally overwriting existing data, which can happen with square bracket assignment.
- In the example,
config.setdefault("language", "en")successfully adds the new key because"language"is missing. - Conversely, the method does nothing when it sees
config.setdefault("theme", "light")since the"theme"key is already present, leaving its original value untouched.
Working with defaultdict for automatic key creation
from collections import defaultdict
word_count = defaultdict(int)
for word in ["apple", "banana", "apple", "cherry"]:
word_count[word] += 1
print(dict(word_count))--OUTPUT--{'apple': 2, 'banana': 1, 'cherry': 1}
The defaultdict from the collections module is a lifesaver when you need to handle missing keys automatically. By initializing it with defaultdict(int), you tell it that any new key should get a default value of 0. This is perfect for tasks like counting items.
- It lets you modify a key's value directly, like with
word_count[word] += 1, without first checking if the key exists. This completely avoidsKeyErrorexceptions for this common pattern.
Handling nested dictionaries with dynamic path creation
def add_nested(d, path, value):
keys = path.split('.')
for key in keys[:-1]:
d = d.setdefault(key, {})
d[keys[-1]] = value
user_data = {}
add_nested(user_data, "profile.contact.email", "[email protected]")
print(user_data)--OUTPUT--{'profile': {'contact': {'email': '[email protected]'}}}
This custom add_nested function is a powerful way to add values deep inside a dictionary using a simple string path. It saves you from manually checking if each nested key exists before creating the next one, which can be quite tedious.
- The function first splits a path like
"profile.contact.email"into a list of keys. - It then iterates through the path, using
setdefault(key, {})to create an empty dictionary for each key that doesn't already exist. - Finally, it assigns your value to the last key in the path, completing the nested structure.
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Common errors and challenges
Even with simple dictionary operations, you can run into common pitfalls like KeyError or accidental overwrites; here’s how to avoid them.
Avoiding KeyError when accessing non-existent keys
A KeyError is one of the most frequent issues you'll face. It happens when you try to access a key that doesn't exist in the dictionary. For example, trying to read my_dict["non_existent_key"] will crash your program if that key isn't there.
- To prevent this, you can check if a key exists before trying to access it using the
inkeyword, likeif "my_key" in my_dict:. - Alternatively, use the
.get()method. It safely returnsNone(or a default value you specify) if the key is missing, instead of raising an error.
Avoiding issues with mutable {} default parameters
A subtle but tricky issue arises when you use a mutable object like an empty dictionary {} as a default argument in a function. Python creates this default dictionary only once when the function is defined, not each time it's called. This means any changes made to the dictionary in one function call will persist in subsequent calls, leading to unexpected behavior.
- The standard practice is to use
Noneas the default value and then create a new dictionary inside the function if one isn't provided. This ensures each function call starts with a fresh, empty dictionary.
Preventing accidental key overwriting with [] notation
While using square bracket notation [] is great for adding or updating keys, it can also be a source of bugs. If you assign a value to a key that already exists, you'll silently overwrite its previous value without any warning. This can lead to data loss if you're not careful.
- Before assigning a value, you can perform a quick check to see if the key is already in the dictionary.
- For a more direct approach, the
setdefault()method is perfect. It only adds the key-value pair if the key doesn't already exist, protecting your existing data from being overwritten.
Avoiding KeyError when accessing non-existent keys
It's easy to trigger a KeyError when you assume a key exists. If you try to retrieve a value using square brackets and the key isn't in the dictionary, your script will halt. See this common mistake in action below.
user_settings = {"theme": "dark", "notifications": True}
font_size = user_settings["font_size"] # This will raise KeyError
print(f"Font size: {font_size}")
The code fails because it tries to access the "font_size" key, which isn't defined in the user_settings dictionary. This direct access attempt triggers the error. The following example shows a safer approach to prevent this crash.
user_settings = {"theme": "dark", "notifications": True}
font_size = user_settings.get("font_size", 12) # Uses default value if key doesn't exist
print(f"Font size: {font_size}")
The get() method provides a safe way to access keys that might not exist. Instead of raising a KeyError, it returns a default value if the key is missing. In the example, user_settings.get("font_size", 12) searches for the "font_size" key. Because the key isn't found, the method returns the specified default, 12, preventing the program from crashing. This is especially useful when dealing with optional configuration settings or unpredictable data.
Avoiding issues with mutable {} default parameters
Using a mutable default argument, such as an empty dictionary {}, can introduce subtle bugs. Python creates this default object only once, so it’s shared across all function calls. This means modifications from one call unexpectedly carry over to the next. The following code demonstrates this behavior in action.
def add_score(scores_dict={}):
scores_dict["player1"] = scores_dict.get("player1", 0) + 100
return scores_dict
result1 = add_score()
print(result1)
result2 = add_score()
print(result2) # Shows {'player1': 200} instead of {'player1': 100}
Because the default scores_dict is shared, the first call adds a player. The second call modifies that same dictionary, incrementing the score instead of starting fresh. The example below shows how to correct this behavior.
def add_score(scores_dict=None):
if scores_dict is None:
scores_dict = {}
scores_dict["player1"] = scores_dict.get("player1", 0) + 100
return scores_dict
result1 = add_score()
print(result1)
result2 = add_score()
print(result2) # Correctly shows {'player1': 100}
The corrected add_score function sets the default parameter to None. Inside the function, it checks if scores_dict is None and creates a new empty dictionary {} if so. This ensures each function call gets a fresh dictionary, preventing the shared state issue. It's a crucial pattern when defining functions with mutable default arguments like lists or dictionaries, as it guarantees predictable behavior and avoids bugs from one call affecting another.
Preventing accidental key overwriting with [] notation
While convenient, the [] notation for assignment doesn't warn you before replacing an existing value. This behavior can lead to subtle bugs, especially when a value is unintentionally overwritten with a different data type. The following code shows this problem in action.
customer = {"id": 123, "name": "John"}
customer["id"] = "A123" # Overwrites the integer ID with a string
print(customer)
The assignment customer["id"] = "A123" silently replaces the original integer with a string. This can cause data type mismatches later, breaking any logic that expects the ID to be a number. The following example demonstrates a safer approach.
customer = {"id": 123, "name": "John"}
if "id" not in customer:
customer["id"] = "A123"
else:
customer["customer_id"] = "A123" # Use a different key
print(customer)
To prevent accidental overwrites, check if a key exists before assigning a value with []. The example uses an if "id" not in customer: condition to protect the original data. Because the id key is already present, the code avoids overwriting it and instead creates a new customer_id key. This is a safe way to merge data without losing important information, especially when you can't be sure what keys a dictionary already contains.
Real-world applications
With an understanding of potential errors, you can confidently apply these dictionary methods to build practical applications like contact managers and text analyzers.
Building a contact manager with update() and bracket notation
This example combines bracket notation for adding a single entry with the update() method for bulk additions to build a simple contact manager from scratch.
contacts = {}
# Add new contact using bracket notation
contacts["John"] = {"phone": "555-1234", "email": "[email protected]"}
# Add multiple contacts using update()
contacts.update({
"Sarah": {"phone": "555-5678", "email": "[email protected]"},
"Mike": {"phone": "555-9012", "email": "[email protected]"}
})
print(contacts["Sarah"])
The code initializes an empty dictionary, contacts, and populates it using two different methods. This demonstrates how you can manage a collection of data where each key is a name and the value is a nested dictionary of details.
- First, it adds a single entry for "John" using simple square bracket
[]assignment. - Then, it uses the
update()method to efficiently merge two new contacts, "Sarah" and "Mike", in a single operation.
Finally, the print() statement accesses and displays Sarah's complete contact information by referencing her key.
Creating a frequency counter for text analysis with setdefault()
This example uses the setdefault() method to build a frequency counter, a common tool in text analysis for tallying how often each word appears.
text = "to be or not to be that is the question"
word_freq = {}
for word in text.split():
word_freq.setdefault(word, 0)
word_freq[word] += 1
print(word_freq)
This code builds a dictionary that maps each word in a sentence to its number of appearances. It loops through every word from the input string. The setdefault(word, 0) method ensures each word has an entry in the word_freq dictionary before you try to increment its count.
- If a word is new,
setdefault()initializes its count to0. - The next line,
word_freq[word] += 1, always works because the key is guaranteed to exist.
This pattern is a concise way to handle counting without an explicit if/else block to check for new words.
Get started with Replit
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