Instead of this:

# The word here is "word"
print("_ _ _ _")

You could use this:

letters = ["_","_","_","_"]
print(letters[0], letters[1], letters[2], letters[3])

The output would be

____

And if a letter would be guessed, simply redefine the letter.

# Someone guessed the letter "o"
letters[1] = "o"
print(letters[0], letters[1], letters[2], letters[3])

Output would now be

_o__

This is just a rough mock-up, so you'll have to change it a bit to fit it into your program. I can help you with it if you'd like.

@Axrevyn I get the idea, but won't that work only with only one type of length for example:
letters = ["","","",""]
print(letters[0], letters[1], letters[2], letters[3])
↑ the above code type will only work with four letter words not with words with other lengths
I will try it to make it more flexible but if possible
give me a more flexible idea

and thank you for replying

@Aayan11 It was a rough mock-up. Would you like me to help?

@Aayan11

import sys

# Reads the number of letters
lm = int(input("Enter number of letters: "))
lm2 = 0

# Defines the list
letters = [None, None, None, None, None, None, None, None, None, None]
#As many "None" values as you need, this one will only
#support as many as 10 letters because there is only 10 None values

while (lm == lm2) is False:
  if bool(letters[int(lm2)]) is False:
    letters[int(lm2)] = "_"
  lm2 = lm2 + 1

# This function prints the parts of the list that are not None values
def word_print():
  lm_check = 0
  while (lm_check == lm) is False:
    sys.stdout.write(letters[int(lm_check)])
    sys.stdout.flush()
    lm_check = lm_check + 1

# Call the function
word_print()

In this case, just define lm as the number of letters in the word and you can let the rest of the code do its thing.

@ParkerTaylor1 sup