Yahtzee

Hello hello hello!

I made Yahtzee! (Kinda)

So what is Yahtzee?

Yahtzee is a popular dice game where you have 5 dice (each dice having 6 sides, and the numbers 1 - 6 written on the sides. Just normal dice). The aim of the game is to roll those dice and to try to get at least 3 dice of the same value. The full game has a few more stuff, what I have done is a bit more simplified. Rolling all five dice with the same number (like all of them have the number 2) gets you the most points possible. That is called Yahtzee. (I think you’re supposed to shout that out loud if you get it xDD)

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My version

So like I said earlier, what I did is a simplified version of the game. Mine is kinda a simulation.

• You will be able to either roll the dice manually (by pressing enter) or by doing it automatically for a number of times set by you (careful not to put a value too big or it’ll crash!).

• At the end of the simulations, you will be given a summary with how many rolls you did, how much times you got 3 Of A Kinds/4 Of A Kinds/Yahtzees, and your total points. In this version, I put 3 Of A Kinds at 6 pts, 4 Of A Kinds at 12 pts, and Yahtzees at 50 pts.

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How this was made

Ok, so first of all, I have my list containing 5 dice. I then rolled a random number from 1 to 6 for each of the 5 dice. remember that lists start at index 0.

Next, instead of using loads and loads of if statements to check if the numbers are the same, I just used the sort(). This sorts the dice from smallest to largest.

So for example, if I rolled [5] [6] [5] [5] [1], the sort() will sort them like this: [1] [5] [5] [5] [6]. As you can see, I have a 3 Of A Kind.

Next, I use a bit of conditionals to determine if I scored anything. Like if I scored a Yahtzee, that would mean that all the dice are the same. So I can just do if dice[0] == dice[4]: which checks if the 1st dice equals the last dice. Since the dice are already arranged from smallest to largest, then it sees that I got a Yahtzee!

Lets go back to my 1st example.

These are my dice: [1] [5] [5] [5] [6] and they are sorted from smallest to largest. The first ifstatement checks if there is Yahtzee. Is the first index equal to the last one? No, so no Yahtzee.

Then, it checks if its a 4 Of A Kind like this:
elif dice[0] == dice[3] or dice[1] == dice[4]:
Again, that condition isn’t verified.

Last conditional, it checks if there is a 3 Of A Kind:
elif dice[0] == dice[2] or dice[1] == dice[3] or dice[2] == dice[4]:
Aha! So we can see that dice[1] == dice[3] which means that the dice at index 1 = the dice at the index 3. This means that I have scored a 3 Of A Kind!

(I hope that wasn’t too long/unnecessarily boring or complicated ;)

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Chances of getting a Yahtzee

Planning on getting those 50 points? You’ll have to be very, very, very, very lucky. Lets do the math:

There are 5 dice, each with 6 sides. This means there are 6 x 6 x 6 x 6 x 6 = 6^5 = 7776 possible different combinations. A lot.

So if you want all the dice to have the same numbers; you have 6 possibilities (five 1s, five 2s, five 3s, etc.).

Next, we divide the number of possible Yahtzees (6) by the total possible rolls (7776), you get 6/7776 = 1/1296.

Yep, the odds of getting a Yahtzee is 1 chance over 1296. That’s about 0.08 percent.

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Some gameplay

As you can see, I’ve rolled 10 times, and only gotten one 3 Of A Kind, no Yahtzee (duh).



I roll 100 times, and I’ve gotten six 4 Of A Kinds and nineteen 3 Of A Kinds, still no Yahtzee.



I roll 1000 times, twenty-two 4 Of A Kinds and one hundred and eighty eight 3 Of A Kinds, and still no Yahtzees again.


But now I rolled 10000 times, and I’ve finally gotten 4 Yahtzees with almost two hundred 4 Of A Kinds and almost two thousand 3 Of A Kinds.


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Well, that’s all I think. Try this out and tell me what you think. I find it mind boggling how many possibilities there are in only 5 dice, and how hard it is to get a Yahtzee.

So if y’all every play the actual game, just know that you’ll have to throw dice a few thousand times to get some Yahtzees!

Everyone have an amazing day! =)