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I Need Help...

print threeNum
b. check if index 0 is < 5
i. if threeNum[0] < 5, replace index 0 with the string: “small”
ii. else, replace index 0 with a string: “large”
c. print threeNum

i have to do this, but when i put the proper signs in, it throws a error at me. Any ideas for what i can do to fix it?

Answered by SUHASTADIPARTH1 [earned 5 cycles]

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Comments

SUHASTADIPARTH1

You need to do this:


threeNum = ["2", "7", "9"]

if int(threeNum[0]) > 5:
    threeNum[0] = 'small'
else:
    threeNum[0] = 'large'

print(threeNum)

You need to convert that first index of the list into a integer, since you have all strings in your list

If you have a list of strings, convert the indices to integers

or

make the list all integers

do

threeNum = [2, 7, 9] instead of threeNum = ["2", "7", "9"]

THANK YOU!!! THAT WORKED.

@SUHASTADIPARTH1

SUHASTADIPARTH1

np :)

:) hope you and everyone else is safe during COVID-19.

@SUHASTADIPARTH1

SUHASTADIPARTH1

Yes!

tbh i hope COVID-19 ends soon. COVID is getting old, quick. if you or anyone on here got hit by Hurricane zeta, i hope yall are safe and sound.

@SUHASTADIPARTH1

You forgot that you are comparing to an integer!
Your list type is a string
You are comparing an int

so it will never be true!
Change your code to:


if threeNum[0] == "5":
  threeNum[0] = "small"
  print(threeNum)
elif threeNum[0] == "5":
  threeNum[0] = "big"
  print(threeNum)

or:


if int(threeNum[0]) == 5:
  threeNum[0] = "small"
  print(threeNum)
elif int(threeNum[0]) == 5:
  threeNum[0] = "big"
  print(threeNum)

hey, thanks for the help.

np

how have you been during COVID?

good

thats good.

thanks! You?

im ok. thx for asking.

hey y'all, i need some help.