How do you make a text adventure game in python

It's pretty simple, just create a story, and at each important point in the story, give the player a two options. If they pick the wrong option, they die, or something like that. Here's a simple one:


#get the player's name
name = input("Name:  ")
print("Hello " + name)
print("You are on an adventure, what do you want to do?")
print("[1] Hunt a dragon     [2] Jump in a hole filled with spikes")
#then get the player's choice
choice = input()
#check to see what the player chose to do
if choice == '1':
  print("You attack a dragon and killed it")
  #Now give them another choice to keep the story going
  print("[1] Jump in a hole filled with spikes    [1] Hunt another dragon")
  choice2 = input()
  if choice2 == '1':
    print("You died...")
  elif choice2 == '2':
   print("You hunted a dragon and won!")
   #Then you continue on
elif choice == '2':
  #This is the result of them choosing to jump into the hole the first time
  print("You died...")

You can make the story as complicated or uncomplicated as you like, but have fun with it.

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SandwichBlamwich

@InvisibleOne
I can only do two choices, choice3 does not work?
I am new to python :p

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InvisibleOne

It should just be another elif


print("[1] Do something")
print("[2] Say Hi")
print("[3] Leave")

choice = input("=> ")

if choice == '1':
  print("doing something...")

elif choice == '2':
  print("Hi!")

elif choice == '3':
  exit()

@SandwichBlamwich

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SandwichBlamwich

@InvisibleOne no i mean in "if choice3 == '2':"
does not work (without the "")

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InvisibleOne

Hmm... Could I see the code in context? @SandwichBlamwich

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SandwichBlamwich

@InvisibleOne this is a snippet, i have the choice3 = input(), just i did not copy it.
'''
if choice3 == '1':
print("it was a trap! as you pick up the bottle, placing coins on the table, the shopkeeper pounces and takes you away!")
print("the end...")
elif choice3 == '2':
print("you pass through and continue on. ")
print("it starts to get dark...")
print("[1] set up camp [2] continue")
choice = input("")
if choice == '1':
print("test")
elif choice == '2':
print("test")
'''

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SandwichBlamwich

@InvisibleOne
elif choice3 == '2':
does not work. the if choice3 == '1':
works...

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SandwichBlamwich

elif choice3 == '2': is the code that is not working...
if choice3 == '1': works!?

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InvisibleOne

I'm not sure what the problem is, unless it is an indentation issue. Here's an example code yours should be something like this: https://replit.com/@InvisibleOne/example#main.py @SandwichBlamwich

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Coder100

Hi! Try out some tutorials:
https://www.derekshidler.com/how-to-create-a-text-based-adventure-and-quiz-game-in-python/
https://blog.trinket.io/python-text-adventure/
https://www.techradar.com/how-to/computing/how-to-code-your-own-adventure-game-in-python-1313296

I'll make a tutorial on this soon too

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Bookie0

hi there!

first of all to make a text adventure game, you should choose your plot story. It could be anything, like a mountain trailing hike, or a post apocalyptic society, etc. Then, make some questions.

The 1st question could be like do you want to run away or fight a monster. Then, include a variable to keep track of how brave you are; for brave actions + 1 for coward actions - 1. Here is a list of some questions:

fight/run away
turn light on/dont
save person/leave them to die
share food/dont
share water/dont
go to plains/go to mountain
cross bridge/swim
go inside town/stay in fields
go inside motel/go to barn

and here is a text adventure game i made a while ago:
https://repl.it/talk/share/OBLIVION/37512

also here some resources to help you: http://coding-grace-guide.readthedocs.io/en/latest/guide/lessonplans/beginners-python-text-based-adventure.html

https://letstalkdata.com/2014/08/how-to-write-a-text-adventure-in-python/

https://trinket.io/python/e5a03e7cbc

https://www.derekshidler.com/how-to-create-a-text-based-adventure-and-quiz-game-in-python/

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PattanAhmed

@rperm Hi,
Follow up with this video...
It will be really helpful.
Click here
Thanks!

Hope this helps