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The End Of The Outsider

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The End Of The Outsider / Logan University

vdv= k'dx. ∫vdv= ∫k'dx. v 2 = 2k'x + 2C' where C' is a constant. v=√ (kx+C) Now,v=dx/dt. dx/√ (kx+C) =dt. ∫dx/√ (kx+C) =∫dt. x = (αt+β) 2 ,where α and β are some constants. Now ,I would like to know how do we solve the equation d 2 x/dt 2 = k' by direct integration.
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The first easiest methods for finding the number of valence electrons for carbon atom or any different atoms, first look at the periodic table, if you prope

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